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		<h1>MỐI QUAN HỆ GIỮA CÁC CHẤT VÔ CƠ</h1>
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			<li>Thứ tư - 11/11/2020 09:05</li>
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			Sơ đồ mối quan hệ giữa các chất vô cơ<br />- HS lập sơ đồ mối quan hệ <br />- HS lấy PTHH để thực hiện mỗi chuyển hóa
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			<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>Bài 1</b>: Viết PTHH trực tiếp tạo ra ZnCl<sub>2</sub> bằng 8 cách</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Hướng dẫn:&nbsp;&nbsp;&nbsp; Zn + Cl<sub>2</sub> <span lang="PL" style="font-family:Symbol">®</span> ZnCl<sub>2</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Zn + 2HCl <span lang="PL" style="font-family:Symbol">®</span> ZnCl<sub>2</sub> + H<sub>2</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; </b>Zn + CuCl<sub>2</sub> <span lang="PL" style="font-family:Symbol">®</span> ZnCl<sub>2</sub> + Cu</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; ZnO + 2HCl <span lang="PL" style="font-family:Symbol">®</span> ZnCl<sub>2</sub> + H<sub>2</sub>O</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Zn(OH)<sub>2</sub> + 2HCl <span lang="PL" style="font-family:Symbol">®</span> ZnCl<sub>2</sub> + 2H<sub>2</sub>O</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; </b>ZnS + 2HCl <span lang="PL" style="font-family:Symbol">®</span> ZnCl<sub>2</sub> + H<sub>2</sub>S</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; ZnCO<sub>3</sub> + 2HCl <span lang="PL" style="font-family:Symbol">®</span> ZnCl<sub>2</sub> + H<sub>2</sub>O + CO<sub>2</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; </b>ZnSO<sub>3</sub> + 2HCl <span lang="PL" style="font-family:Symbol">®</span> ZnCl<sub>2</sub> + H<sub>2</sub>O + SO<sub>2</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>Bài 2</b>: Chọn 9 chất rắn khác nhau để khi cho vào dd HCl tạo ra 9 khí khác nhau</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Hướng dẫn: Chọn 9 chất rắn khác nhau để được 9 chất khía là</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; H<sub>2</sub>; CO<sub>2</sub>; SO<sub>2</sub>; H<sub>2</sub>S; Cl<sub>2</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>Bài 3</b>: Cho 10 gam hỗn hợp các kim loại Fe và Cu vào dd CuSO<sub>4</sub> dư. Sau khi phản ứng xẩy ra hoàn toàn thu được chất rắn có khối lượng 11 gam.</span></span></span>
<ol style="list-style-type:lower-alpha">
	<li><span style="font-size:14pt"><span style="tab-stops:list 36.0pt left 144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Tính % theo khối lượng mỗi kim loại trong hỗn hợp đầu</span></span></span></li>
	<li><span style="font-size:14pt"><span style="tab-stops:list 36.0pt left 144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Nếu cho 10 gam hỗn hợp các kim loại trên vào dd H<sub>2</sub>SO<sub>4</sub> đ,n vừa đủ thì thu được bao nhiêu lit khí thoát ra (đktc)</span></span></span></li>
</ol>
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Hướng dẫn giải:</span></span></span>

<ol style="list-style-type:lower-alpha">
	<li><span style="font-size:14pt"><span style="tab-stops:list 38.25pt left 144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Fe&nbsp; +&nbsp; CuSO<sub>4</sub>&nbsp; <span lang="PL" style="font-family:Symbol">®</span>&nbsp; FeSO<sub>4</sub>&nbsp; + Cu</span></span></span></li>
</ol>
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Gọi số mol của Fe trong hỗn hợp là x (x,y&gt;0)</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; số mol của Cu trong hỗn hợp là y</span></span></span><br  />
<img alt="" height="186" src="https://khobaitap.com/uploads/news/2020_11/image_126.png" width="417" /><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>Bài 4</b>: Chỉ dùng CO<sub>2</sub> có thể phân biệt các dd riêng biệt mất nhãn sau không? Nếu có hãy trình bày cách làm:&nbsp; Na<sub>2</sub>CO<sub>3</sub>; NaOH; HCl; Ca(OH)<sub>2</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Hướng dẫn giải:</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp; -Sục CO<sub>2</sub> vào các dd</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp; Nếu có chất kết tủa trắng xuất hiện là dd Ca(OH)<sub>2</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">- Cho dd Ca(OH)<sub>2</sub> vào 3 dd còn lại: Nếu có kết tủa xuất hiện là dd Na<sub>2</sub>CO<sub>3</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">- Cho dd Na<sub>2</sub>CO<sub>3</sub> vào 2 dd còn lại: Nếu có khí thoát ra là dd HCl</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>Bài 5</b>: Cho sản phẩm tạo thành khi nung 2,8 gam bột Fe với 0,8 gam bột S vào 500 ml dd HCl thu được dd A và hỗn hợp khí. Để trung hòa dd A phải dùng 62,5 ml dd NaOH 0,1M.</span></span></span>

<ol style="list-style-type:lower-alpha">
	<li><span style="font-size:14pt"><span style="tab-stops:list 36.0pt left 144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Tính V khí (đktc) thoát ra</span></span></span></li>
	<li><span style="font-size:14pt"><span style="tab-stops:list 36.0pt left 144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Tính C<sub>M</sub> dd HCl đã dùng</span></span></span></li>
	<li><span style="font-size:14pt"><span style="tab-stops:list 36.0pt left 144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Trình bày phương pháp hóa học phân biệt 2 chất rắn riêng biệt là bột Fe và bộ S</span></span></span></li>
	<li><span style="font-size:14pt"><span style="tab-stops:list 36.0pt left 144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Trình bày phương pháp tách riêng từng chất ra khỏi hỗn hợp bột Fe và S</span></span></span></li>
</ol>
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Hướng dẫn giải:</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Fe&nbsp; + S <span lang="PL" style="font-family:Symbol">®</span> FeS&nbsp; (1)</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 0,025&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 0,025&nbsp;&nbsp; 0,025</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Fe + 2HCl <span lang="PL" style="font-family:Symbol">®</span> FeCl<sub>2</sub> + H<sub>2</sub> (2)</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 0,025&nbsp;&nbsp;&nbsp; 0,05&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 0,025</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;FeS + 2HCl <span lang="PL" style="font-family:Symbol">®</span> FeCl<sub>2</sub> + H<sub>2</sub>S&nbsp; (3)</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 0,025&nbsp;&nbsp;&nbsp;&nbsp; 0,05&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 0,025</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; NaOH + HCl <span lang="PL" style="font-family:Symbol">®</span> NaCl + H<sub>2</sub>O (4)</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 0,00625&nbsp;&nbsp;&nbsp; 0,00625</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">a. V khí = 0,05 . 22,4 = 11,2 lit</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">b. nHCl = 0,05 + 0,05 + 0,00625 = 0,10625 mol</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp; C<sub>M</sub> dd HCl = 0,10625/ 0,5 = 0,2125M</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">c. Cho dd HCl vào 2 chất bột trên: Nếu có khí thoát ra là Fe, không có hiện tượng gì là S</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">d. Cho hỗn hợp vào dd HCl, lọc lấy chất rắn là S. Cho dd NaOH dư vào dd nước loc, lấy kết tủa nung đến khối lượng không đổi được Fe<sub>2</sub>O<sub>3</sub>. Dẫn H<sub>2</sub> dư đi qua, nung nóng được Fe</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif"><b>Bài 6</b>: Viết PTHH thực hiện dãy chuyển hóa sau</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; BaCO<sub>3</sub> <span lang="PL" style="font-family:Symbol">®</span> X <span lang="PL" style="font-family:Symbol">®</span> Y <span lang="PL" style="font-family:Symbol">®</span> Z <span lang="PL" style="font-family:Symbol">®</span> BaCO<sub>3</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">Hướng dẫn:&nbsp; X: BaO</span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Y: BaCl<sub>2</sub></span></span></span><br  />
<span style="font-size:14pt"><span style="tab-stops:144.75pt"><span style="font-family:&#039;Times New Roman&#039;,serif">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Z: Ba(NO<sub>3</sub>)<sub>2</sub></span></span></span><br  />
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