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		<h1>Cách giải Bài tập Định luật Ôm cho đoạn mạch</h1>
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			<li>Thứ ba - 17/08/2021 04:15</li>
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			Bài 1: Cho mạch điện có sơ đồ như hình vẽ Cho biết: R1 = 3Ω, R2 = 6Ω, R3 = 6Ω, UAB = 3V. Tìm:
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<p>a) Điện trở tương đương của đoạn mạch AC.</p>

<p>b) Cường độ dòng điện qua R<sub>3</sub>.</p>

<p>c) Hiệu điện thế giữa hai điếm A và C.</p>

<p>d) Cường độ dòng điện qua R<sub>1</sub>&nbsp;và R<sub>2</sub>.<br  />
Giải<br  />
<img alt="" height="305" src="https://khobaitap.com/uploads/news/2021_08/image_1.png" width="507" /><br  />
<img alt="" height="272" src="https://khobaitap.com/uploads/news/2021_08/image_2.png" width="467" /><br  />
<b>Bài 2:</b>&nbsp;Cho mạch điện như hình vẽ. Biết R<sub>1</sub>&nbsp;= 4 Ω; R<sub>2</sub>&nbsp;= 6 Ω; R<sub>3</sub>&nbsp;= 10 Ω. Đặt vào hai đầu AB một hiệu điện thế U = 10 V. Hãy xác định:<br  />
<img alt="" height="92" src="https://khobaitap.com/uploads/news/2021_08/image_3.png" width="238" /></p>

<p>a) Điện trở tương đương của mạch</p>

<p>b) Cường độ dòng điện qua mỗi điện trở và trong mạch chính</p>

<p>c) Hiệu điện thế hai đầu mỗi điện trở.</p>

<p><b>Hướng dẫn giải:</b></p>

<p>Sơ đồ mạch điện (R<sub>1</sub>&nbsp;nt R<sub>2</sub>) // R<sub>3</sub></p>

<p>a) Điện trở tương đương của mạch điện<br  />
<img alt="" height="289" src="https://khobaitap.com/uploads/news/2021_08/image_4.png" width="340" /></p>

<p>c) Hiệu điện thế hai đầu R<sub>1</sub>&nbsp;là: U<sub>1</sub>&nbsp;= I<sub>12</sub>.R<sub>1</sub>&nbsp;= 1.4 = 4 V</p>

<p>Hiệu điện thế hai đầu R<sub>2</sub>&nbsp;là: U<sub>2</sub>&nbsp;= I<sub>12</sub>.R<sub>2</sub>&nbsp;= 1.6 = 6 V</p>

<p>Hiệu điện thế hai đầu R<sub>3</sub>&nbsp;là: U<sub>3</sub>&nbsp;= U = 10 V.<br  />
<b>Bài 3:</b>&nbsp;Cho mạch điện như hình vẽ: R<sub>1</sub>&nbsp;= R<sub>3</sub>&nbsp;= 3Ω, R<sub>2</sub>&nbsp;= 2Ω, R<sub>4</sub>&nbsp;= 1Ω, R<sub>5</sub>&nbsp;= 4Ω. Cường độ dòng điện qua mạch chính là 3A. Tìm<br  />
<img alt="" height="125" src="https://khobaitap.com/uploads/news/2021_08/image_5.png" width="266" /></p>
&nbsp;

<p>a. U<sub>AB</sub></p>

<p>b. Hiệu điến thế hai đầu mỗi điện trở.<br  />
<img alt="" height="469" src="https://khobaitap.com/uploads/news/2021_08/image_6.png" width="403" /></p>
<b>Bài 4:</b>&nbsp;Cho mạch điện như hình 5. Trong đó: R<sub>1</sub>&nbsp;= 10Ω; R<sub>2</sub>&nbsp;= 3Ω; R<sub>3</sub>&nbsp;= R<sub>4</sub>&nbsp;= 6Ω; R<sub>5</sub>&nbsp;= 4Ω. Cường độ dòng điện chạy trong mạch chính là 6A. Tính cường độ dòng điện qua mỗi điện trở.<br  />
<img alt="" height="178" src="https://khobaitap.com/uploads/news/2021_08/image_7.png" width="276" /><br  />
<img alt="" height="342" src="https://khobaitap.com/uploads/news/2021_08/image_8.png" width="421" />
<p>Vì đoạn CD mắc nối tiếp R<sub>1</sub>&nbsp;nên I<sub>CD</sub>&nbsp;= I<sub>1</sub></p>

<p>Hiệu điện thế 2 đầu đoạn CD: U<sub>CD</sub>&nbsp;= I<sub>CD</sub>. R<sub>23</sub>&nbsp;= 1.2 = 2V</p>

<p>Cường độ dòng điện qua R<sub>2</sub>:<br  />
<img alt="" height="320" src="https://khobaitap.com/uploads/news/2021_08/image_9.png" width="267" /><br  />
<b>Bài 5:</b>&nbsp;Cho mạch điện như hình vẽ, trong đó R<sub>1</sub>&nbsp;= 5 Ω, R<sub>2</sub>&nbsp;= 12 Ω, R<sub>3</sub>&nbsp;= 8 Ω, R<sub>4</sub>&nbsp;= 20 Ω. hiệu điện thế là 30V.<br  />
<img alt="" height="94" src="https://khobaitap.com/uploads/news/2021_08/image_10.png" width="285" /><br  />
&nbsp;</p>

<p>a) Tính điện trở tương đương của toàn mạch</p>

<p>b) Tìm cường độ dòng điện qua mỗi điện trở</p>

<p>c) Tính hiệu thế hai đầu các điện trở<br  />
Giải<br  />
&nbsp;</p>

<p>Viết sơ đồ mạch: R<sub>1</sub>&nbsp;nt &#91;(R<sub>2</sub>&nbsp;nt R<sub>3</sub>) // R<sub>4</sub>&#93;</p>

<p>a) Điện trở tương đương cụm R<sub>234</sub>&nbsp;là:<br  />
<img alt="" height="229" src="https://khobaitap.com/uploads/news/2021_08/image_12.png" width="352" /><br  />
&nbsp;</p>

<p>Cường độ dòng điện qua điện trở R<sub>1</sub>: I<sub>1</sub>&nbsp;= I = 2A.</p>

<p>Cường độ dòng điện qua R<sub>2</sub>&nbsp;và R<sub>3</sub>&nbsp;là: I<sub>23</sub>&nbsp;= I<sub>2</sub>&nbsp;= I<sub>3</sub>.</p>

<p>Cường độ dòng điện qua R<sub>4</sub>&nbsp;là I<sub>4</sub>.</p>

<p>Ta có U<sub>23</sub>&nbsp;= U<sub>4</sub><br  />
<img alt="" height="60" src="https://khobaitap.com/uploads/news/2021_08/image_13.png" width="206" /></p>

<p>Mặt khác I<sub>23</sub>&nbsp;+ I<sub>4</sub>&nbsp;= I<sub>1</sub>&nbsp;= 2A. Nên I<sub>23</sub>&nbsp;= I<sub>4</sub>&nbsp;= 1A.</p>

<p>c) Hiệu điện thế hai đầu R<sub>1</sub>&nbsp;là: U<sub>1</sub>&nbsp;= I<sub>1</sub>.R<sub>1</sub>&nbsp;= 2.5 = 10 V</p>

<p>Hiệu điện thế hai đầu R<sub>2</sub>&nbsp;là: U<sub>2</sub>&nbsp;= I<sub>2</sub>.R<sub>2</sub>&nbsp;= 1.12 = 12 V</p>

<p>Hiệu điện thế hai đầu R<sub>3</sub>&nbsp;là: U<sub>3</sub>&nbsp;= I<sub>3</sub>.R<sub>3</sub>&nbsp;= 1.8 = 8 V</p>

<p>Hiệu điện thế hai đầu R<sub>4</sub>&nbsp;là: U<sub>4</sub>&nbsp;= I<sub>4</sub>.R<sub>4</sub>&nbsp;= 20 V<br  />
<b>Bài 6:</b>&nbsp;Cho mạch điện như hình vẽ: U<sub>AB</sub>&nbsp;= 12 V; R<sub>1</sub>&nbsp;= 4 Ω; R<sub>2</sub>&nbsp;= R<sub>3</sub>&nbsp;= R<sub>4</sub>&nbsp;= 4 Ω;</p>
<img alt="" height="136" src="https://khobaitap.com/uploads/news/2021_08/image_14.png" width="226" />
<p>a) Tìm điện trở tương đương R<sub>AB</sub>&nbsp;của mạch.</p>

<p>b) Tìm cường độ dòng điện qua các điện trở và hiệu điện thế trên mỗi điện trở<br  />
Giải<br  />
<img alt="" height="558" src="https://khobaitap.com/uploads/news/2021_08/image_15.png" width="567" /></p>
<b>Bài 7:</b>&nbsp;Cho mạch điện như hình vẽ. Trong đó R<sub>1</sub>&nbsp;= R<sub>2</sub>&nbsp;= 4 Ω; R<sub>3</sub>&nbsp;= 6 Ω; R<sub>4</sub>&nbsp;= 3Ω; R<sub>5</sub>&nbsp;= 10 Ω; U<sub>AB</sub>&nbsp;= 24 V. Tính điện trở tương đương của đoạn mạch AB và cường độ dòng điện qua từng điện trở.<br  />
<img alt="" height="100" src="https://khobaitap.com/uploads/news/2021_08/image_16.png" width="308" /><br  />
<img alt="" height="505" src="https://khobaitap.com/uploads/news/2021_08/image_17.png" width="469" /><br  />
Bài tập tự làm<br  />
<span style="font-size:14pt"><span style="font-family:&#039;.VnTime&#039;,sans-serif"><b><span lang="EN-US" style="color:fuchsia">Bµi 1</span></b><span lang="EN-US" style="color:fuchsia"> :</span> Cho m¹ch ®iÖn nh­ h×nh vÏ . HiÖu ®iÖn thÕ gi÷a hai ®Çu ®o¹n m¹ch lµ 70 V . BiÕt R<sub>1</sub> = 15 </span></span><img alt="" height="24" src="https://khobaitap.com/uploads/news/2021_08/image_18.png" width="23" /><span style="font-size:14pt"><span style="font-family:&#039;.VnTime&#039;,sans-serif">&nbsp;, R<sub>2</sub> = 30 </span></span><img alt="" height="24" src="https://khobaitap.com/uploads/news/2021_08/image_19.png" width="23" /><span style="font-size:14pt"><span style="font-family:&#039;.VnTime&#039;,sans-serif">&nbsp;vµ R<sub>3</sub> = 60 </span></span><img alt="" height="24" src="https://khobaitap.com/uploads/news/2021_08/image_20.png" width="23" /><span style="font-size:14pt"><span style="font-family:&#039;.VnTime&#039;,sans-serif">&nbsp;</span></span><br  />
<span style="font-size:14pt"><span style="font-family:&#039;.VnTime&#039;,sans-serif">&nbsp;&nbsp; a, TÝnh ®iÖn trë t­¬ng ®­¬ng cña toµn m¹ch .</span></span><br  />
<span style="font-size:14pt"><span style="font-family:&#039;.VnTime&#039;,sans-serif">&nbsp;&nbsp; b, TÝnh c­êng ®é dßng ®iÖn qua c¸c ®iÖn trë vµ hiÖu ®iÖn thÕ U<sub>23 </sub>.</span></span><br  />
<img alt="" height="160" src="https://khobaitap.com/uploads/news/2021_08/image_21.png" width="344" /><br  />
<img alt="" height="267" src="https://khobaitap.com/uploads/news/2021_08/image_22.png" width="709" /><br  />
<img alt="" height="165" src="https://khobaitap.com/uploads/news/2021_08/image_23.png" width="735" /><br  />
<img alt="" height="168" src="https://khobaitap.com/uploads/news/2021_08/image_24.png" width="715" />
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